Timeline for Is there any efficient solution of the matrix equation AXB + (AXB)' + cX = D
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
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| Nov 18, 2018 at 8:00 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Oct 19, 2018 at 7:47 | answer | added | Federico Poloni | timeline score: 1 | |
| Oct 19, 2018 at 7:00 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Sep 11, 2018 at 22:50 | answer | added | loup blanc | timeline score: 1 | |
| Aug 4, 2018 at 2:59 | comment | added | ericf | I don't know if this works but my first instinct is to try iteratively solving X=(D-AXB-(AXB)')/c. | |
| Aug 2, 2018 at 16:36 | history | edited | John. Tang | CC BY-SA 4.0 |
added 10 characters in body
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| Aug 2, 2018 at 16:30 | review | First posts | |||
| Aug 2, 2018 at 17:30 | |||||
| Aug 2, 2018 at 16:23 | history | asked | John. Tang | CC BY-SA 4.0 |