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Aug 3, 2018 at 4:18 vote accept Changwei Xiong
Aug 2, 2018 at 21:57 comment added Changwei Xiong @Raziel You are right. The minimizer may only be $C^0$ but piecewise $C^1$.
Aug 2, 2018 at 19:40 answer added user127309 timeline score: 4
Aug 2, 2018 at 16:28 comment added Raziel Interpreting the closure as $M \cup \partial M$, it seems to me that, in general, minimizers can have corners. Any non-convex region of $\mathbb{R}^2$ is gives an example.
Aug 2, 2018 at 12:55 answer added Igor Belegradek timeline score: 8
Aug 2, 2018 at 12:13 history asked Changwei Xiong CC BY-SA 4.0