Timeline for Prove that if a group $G$ is generated by all cyclic subnormal subgroups, then every cyclic subgroup is subnormal
Current License: CC BY-SA 4.0
7 events
when toggle format | what | by | license | comment | |
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Aug 4, 2018 at 5:19 | comment | added | Abbas Jafarzadeh | Yes, Of course, $G$ is an arbitrary group. | |
Aug 4, 2018 at 5:12 | vote | accept | Abbas Jafarzadeh | ||
Aug 2, 2018 at 11:33 | answer | added | Denis T | timeline score: 3 | |
Aug 2, 2018 at 10:13 | comment | added | Derek Holt | For finite groups it is not hard to show that both conditions are equivalent to $G$ being nilpotent, but I expect you want the results for all groups. | |
Aug 2, 2018 at 9:40 | history | edited | Martin Sleziak |
Removed the deprecated (abstract-algebra) tag - see the tag info: https://mathoverflow.net/tags/abstract-algebra/info (if there are some other suitable tags, choose them instead.)
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Aug 2, 2018 at 7:30 | review | First posts | |||
Aug 2, 2018 at 7:44 | |||||
Aug 2, 2018 at 7:28 | history | asked | Abbas Jafarzadeh | CC BY-SA 4.0 |