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Timeline for Chain rotation of a point

Current License: CC BY-SA 4.0

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Aug 1, 2018 at 4:13 vote accept Đào Thanh Oai
Aug 1, 2018 at 0:42 answer added Alexey Ustinov timeline score: 2
Aug 1, 2018 at 0:07 history edited Đào Thanh Oai CC BY-SA 4.0
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Jul 31, 2018 at 17:53 comment added Philipp Lampe Using complex numbers, the rotation around $A_i$ is given by $P\mapsto (P-A_i)\omega+A_i=P\omega+(1-\omega)A_i$ where $\omega$ in a primitive $(2n)$-th root of unity. Hence, a sufficient condition for periodicity after $2n$ full cycles is $1+\omega^m+\ldots+\omega^{(2n-1)m}=0$. This fails when $m$ is a multiple of $2n$.
Jul 31, 2018 at 17:48 history edited Đào Thanh Oai CC BY-SA 4.0
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Jul 31, 2018 at 17:42 comment added Đào Thanh Oai Thank You very much for your comment. I have just improved my question from a conjecture to an open problem. @PhilippLampe
Jul 31, 2018 at 17:40 history edited Đào Thanh Oai CC BY-SA 4.0
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Jul 31, 2018 at 17:25 comment added Đào Thanh Oai $(m, n)$=$(2,3)$, $(2, 4)$ are also true......@PhilippLampe
Jul 31, 2018 at 17:17 comment added Đào Thanh Oai Thank You very much, but $(m,n)$=$(3,1)$, $(3, 2)$, $(3,3)$, $(4, 3)$, $(3,4)$... are true @PhilippLampe
Jul 31, 2018 at 16:42 comment added Philipp Lampe Here is a counterexample. Let $(m,n)=(2,1)$ and choose $A_1=(0,0)$ and $A_2\neq A_1$ arbitrary. Then the rotation around $A_1$ is given by $P\mapsto -P$ and the rotation around $A_2$ is given by $P\mapsto 2A_2-P$. In particular, the composition of both rotations is the translation $P\mapsto 2A_2+P$. Hence, whenever we start with a point $P$ that does not lie on the line defined by $A_1$ and $A_2$, then $P$ is not equal to $\pm (P+2\lambda A_2)$ with $\lambda\in\mathbb{Z}\backslash\{0\}$.
Jul 31, 2018 at 16:12 history edited Đào Thanh Oai CC BY-SA 4.0
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Jul 31, 2018 at 16:03 history edited Đào Thanh Oai CC BY-SA 4.0
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Jul 31, 2018 at 15:58 history asked Đào Thanh Oai CC BY-SA 4.0