Timeline for Definition of algebraic de Rham cohomology of non-smooth affine variety
Current License: CC BY-SA 4.0
4 events
| when toggle format | what | by | license | comment | |
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| Oct 27 at 7:53 | comment | added | Z. M | It is slightly strange that Hartshorne did not mention that his algebraic de Rham cohomology computes Grothendieck's infinitesimal cohomology (in char 0). Also, he did not seem to mention that this Betti comparison (can) take values functorially in derived categories. | |
| Jul 30, 2018 at 15:30 | vote | accept | Jürgen Böhm | ||
| S Jul 30, 2018 at 1:46 | history | answered | David Loeffler | CC BY-SA 4.0 | |
| S Jul 30, 2018 at 1:46 | history | made wiki | Post Made Community Wiki by David Loeffler |