Timeline for On the cohomology ring of the Grassmannian
Current License: CC BY-SA 4.0
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| Nov 7, 2018 at 12:07 | history | edited | Michael Albanese | CC BY-SA 4.0 |
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| Jul 6, 2010 at 19:25 | comment | added | Michael Thaddeus | But that's not exactly what he observed. The Weyl group of U(N) is the symmetric group S(N), so the Schubert decomposition W_G/W_P indexes the Grassmannian by the free quotient S(N) / (S(m) x S(N-m)). Whereas the quotient he discusses is {0,1}^(m(N-m)) / (S(m) wreath S(N-m)), which is not free. Both are in natural correspondence with the Young diagrams inside an m by N-m box. To see this for the free quotient, observe that it indexes all possible orderings of m moves across and N-m moves up. | |
| Jul 6, 2010 at 3:07 | history | answered | Allen Knutson | CC BY-SA 2.5 |