Timeline for Relatively countably compact subsets without countably compact closure.
Current License: CC BY-SA 2.5
3 events
| when toggle format | what | by | license | comment | |
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| Jul 6, 2010 at 6:53 | comment | added | Pietro Majer | you're right. I think it can be fixed taking a subspace though... I'll see! | |
| Jul 6, 2010 at 2:24 | comment | added | Joel David Hamkins | Is it really Hausdorff? If $S\subset T\subset\mathbb{N}$ but $S$ is not equivalent to $T$, then the equivalence classes $[S]$ and $[T]$ are distinct elements of $B$, but every open neighborhood of $[S]$ has all but finitely many elements of $S$, co-finitely many of which will be in any given open neighborhood of $[T]$. So it doesn't seem you can separate these two points in $X$. Have I made a mistake? | |
| Jul 6, 2010 at 0:17 | history | answered | Pietro Majer | CC BY-SA 2.5 |