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Aug 2, 2018 at 14:58 history edited Roberto Pagaria CC BY-SA 4.0
added a more precise and general statement.
Jul 28, 2018 at 22:27 comment added R. van Dobben de Bruyn If $V_i$ are allowed to be effective divisors (as opposed to ample divisors; cf. the comments below Sándor Kovács's answer), it seems likely that the following can happen: $V_1$, $V_2$, and $V_3$ are smooth irreducible divisors, $V_{12}$, $V_{23}$, and $V_{31}$ each consist of two smooth components, one of which is in common between all three, and the others intersect in a lower-dimensional variety. Then $V_{123}$ has components of different dimensions. I've tried to construct such an example, but so far have been unsuccessful.
Jul 27, 2018 at 20:17 answer added Sándor Kovács timeline score: 5
Jul 27, 2018 at 15:26 history asked Roberto Pagaria CC BY-SA 4.0