Timeline for Maxed-out Hausdorff metric
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
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| Jul 25, 2018 at 10:06 | answer | added | Arno | timeline score: 1 | |
| Jul 25, 2018 at 10:02 | comment | added | Will Brian | @DominicvanderZypen: A counterexample -- take two copies of (the usual metric on) $[0,1]$, and declare two points in different copies to be distance $1$ apart. Taking $A$ to be one of the two copies maximizes $d_H(A,Y)$. | |
| Jul 25, 2018 at 9:22 | comment | added | Dominic van der Zypen | I think the statement in the question is true if $d:Y\times Y \to [0, s[$ is surjective where $s = \sup\{d(x,y): x,y\in Y\}$. I am trying to prove this. | |
| Jul 25, 2018 at 6:53 | comment | added | Christian Remling | Then another counterexample is $Y=\{ x,y \}$. | |
| Jul 25, 2018 at 5:02 | comment | added | Forever Mozart | I assume >1 point (edited) | |
| Jul 25, 2018 at 5:01 | history | edited | Forever Mozart | CC BY-SA 4.0 |
added 15 characters in body
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| Jul 25, 2018 at 3:22 | comment | added | Christian Remling | No. $Y=\{ y\}$ is a counterexample. | |
| Jul 25, 2018 at 0:41 | history | asked | Forever Mozart | CC BY-SA 4.0 |