Timeline for A rearrangement inequality for exponentiation function
Current License: CC BY-SA 4.0
4 events
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| Jun 19, 2019 at 9:20 | comment | added | Mark Wildon | The answer above would be correct if each factor on the right-hand side was of the form $\sum_{j=1}^n a_{\sigma(j)}^{\alpha_j}$ for some permutation $\sigma$. But in fact $a_i$ is constant within each factor. | |
| Jul 20, 2018 at 11:09 | comment | added | Đào Thanh Oai | I don't think so. Do You prove that $a^d+c^b \ge a^c+a^b$ ? | |
| Jul 20, 2018 at 11:08 | history | edited | Aravind | CC BY-SA 4.0 |
added 110 characters in body
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| Jul 20, 2018 at 11:00 | history | answered | Aravind | CC BY-SA 4.0 |