Timeline for Understanding what it means to be ''of general type''
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jun 15 at 19:46 | comment | added | Adam | Correct me if I am wrong, but I don't believe Bombieri-Lang require X to be smooth. | |
| Jul 31, 2018 at 16:45 | history | edited | user221330 | CC BY-SA 4.0 |
added 1 character in body
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| Jul 20, 2018 at 15:54 | answer | added | Hacon | timeline score: 9 | |
| Jul 20, 2018 at 11:00 | vote | accept | user221330 | ||
| Jul 20, 2018 at 10:47 | comment | added | Ben McKay | Take a variety $X$. Think about the algebra generated by sections of tensor powers of the canonical bundle of $X$. Depending on $X$, this algebra might be the same as the algebra of sections of tensor powers of some line bundle on some, perhaps lower dimensional, variety $Y$. If not, $X$ has general type. So the canonical bundle of $X$ twists around wildly, ``feeling'' all of the dimensions of the variety $X$. | |
| Jul 20, 2018 at 10:39 | review | Close votes | |||
| Jul 26, 2018 at 5:43 | |||||
| Jul 20, 2018 at 10:03 | answer | added | Will Sawin | timeline score: 11 | |
| Jul 20, 2018 at 9:44 | review | First posts | |||
| Jul 20, 2018 at 9:58 | |||||
| Jul 20, 2018 at 9:39 | history | asked | user221330 | CC BY-SA 4.0 |