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Jul 21, 2018 at 14:54 comment added Thomas Bloom It actually goes the other way (because the result becomes weaker with $k\to\infty$): $\lim_{k\to\infty} c_k=0$. I believe it decays at least doubly exponentially in $k$ (with the current best bounds).
Jul 21, 2018 at 5:12 comment added Mohammad Golshani Thanks for the answer. Does Lim$_k~c_k=\infty?$
Jul 19, 2018 at 10:52 history answered Thomas Bloom CC BY-SA 4.0