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Jul 22, 2018 at 19:46 vote accept VSP
Jul 22, 2018 at 19:03 vote accept VSP
Jul 22, 2018 at 19:46
Jul 22, 2018 at 19:03 vote accept VSP
Jul 22, 2018 at 19:03
Jul 22, 2018 at 18:58 vote accept VSP
Jul 22, 2018 at 19:03
Jul 22, 2018 at 18:58 vote accept VSP
Jul 22, 2018 at 18:58
Jul 21, 2018 at 9:25 answer added Mateusz Kwaśnicki timeline score: 6
Jul 20, 2018 at 18:49 history edited Abdelmalek Abdesselam
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Jul 20, 2018 at 15:39 comment added Abdelmalek Abdesselam @prince: thank you for this beautiful question. May I ask about the motivation or context for it?
Jul 19, 2018 at 15:34 answer added Abdelmalek Abdesselam timeline score: 18
Jul 19, 2018 at 12:56 comment added VSP I have checked it many times on Mathematica, the matrix is getting singular only if any two $\alpha_{i}$'s or $\beta_{j}$'s are becoming same, which is not allowed in our problem.
Jul 19, 2018 at 12:42 comment added VSP Bullet51, can you please tell me, why did you mention $\Gamma(2)=\Gamma(1)=1$?
Jul 19, 2018 at 12:15 comment added VSP I don't think, this matrix can get all it's entries equal to 1.
Jul 19, 2018 at 12:10 comment added VSP thanks for replying. Here what are your $ \lambda_{i}$ and $\mu_{j}$?? I have checked it by Mathematica. And I couldn't find any factorization of this matrix too. I have tried it to prove it in many ways. But no success.
Jul 19, 2018 at 11:11 comment added LeechLattice $\Gamma(2)=\Gamma(1)=1$.
Jul 19, 2018 at 10:34 comment added Alex M. Can you give some motivation for why you expect it to be non-singular?
Jul 19, 2018 at 10:29 review First posts
Jul 19, 2018 at 10:33
Jul 19, 2018 at 10:28 history asked VSP CC BY-SA 4.0