Timeline for Average caliper diameter (mean width) of a polyhedron
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
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| Jul 19, 2018 at 6:47 | comment | added | Carlo Beenakker | I added the references for the more general case where also $\delta$ may vary. | |
| Jul 19, 2018 at 6:47 | history | edited | Carlo Beenakker | CC BY-SA 4.0 |
added 416 characters in body
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| Jul 19, 2018 at 2:54 | comment | added | მამუკა ჯიბლაძე | Although it is behind paywall, here is a link in case somebody has access | |
| Jul 18, 2018 at 22:47 | comment | added | JDoe2 | I have also been unable to access this reference. | |
| Jul 18, 2018 at 22:21 | comment | added | JDoe2 | * for every angle * | |
| Jul 18, 2018 at 22:04 | comment | added | JDoe2 | So would I be correct in thinking that if the shape is a polyhedron it's average curvature is zero $$\langle H\rangle = 0$$ From this this would give that: $$\langle C\rangle =\frac{\pi - \delta }{4\pi }\sum_e L_e$$ This makes sense and agrees with the above... but my main problem is I wanted to apply the more general version of non-regular polyhedrons (where delta isn't the same for angle). Do you have any idea how this proof might be extended? | |
| Jul 18, 2018 at 21:51 | history | edited | Carlo Beenakker | CC BY-SA 4.0 |
added 220 characters in body
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| Jul 18, 2018 at 21:45 | history | answered | Carlo Beenakker | CC BY-SA 4.0 |