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Jul 22, 2018 at 18:02 history edited Truong CC BY-SA 4.0
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Jul 17, 2018 at 23:03 history undeleted Truong
Jul 17, 2018 at 12:44 history deleted Truong via Vote
Jul 17, 2018 at 11:02 comment added Jan Bohr As for the 2D-case: I haven't looked into the proof of the claim but I suspect it to rather establish a result that incidentally also holds for the covering space rather than actually lifting the gap. However, it's a good example to have in mind, because the only test examples I could wrap my head around so far were compact (where existence of a spectral gap is clear).
Jul 17, 2018 at 10:59 comment added Jan Bohr Well, I also think that it is true. Unfortunately most references on spectral geometry seem to deal at most with the case that $N$ is compact and $\hat N$ is non-compact. If you have in your mind a useful result from spectral theory (that I could find in any book), I'm happy to hear about it.
Jul 17, 2018 at 9:54 history answered Truong CC BY-SA 4.0