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Jul 13, 2018 at 3:01 comment added Mohan @Kim No, all the sections of $L^2$ comes from $\mathbb{P}^1$ and so no divisor in this system would be irreducible, since any section of $\mathcal{O}_{\mathbb{P}^1}(2)$ vanishes at two points, counted with multiplicity.
Jul 13, 2018 at 1:47 vote accept Kim
Jul 13, 2018 at 1:35 comment added Kim Thanks for the example. Do you think it may have a chance of holding for the elliptic fibration case above?
Jul 13, 2018 at 0:01 history answered Mohan CC BY-SA 4.0