Timeline for Do line bundles with enough sections on surfaces have generic divisors which are irreducible?
Current License: CC BY-SA 4.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jul 13, 2018 at 6:14 | review | Close votes | |||
| Jul 14, 2018 at 18:23 | |||||
| Jul 13, 2018 at 1:47 | vote | accept | Kim | ||
| Jul 13, 2018 at 0:01 | answer | added | Mohan | timeline score: 3 | |
| Jul 12, 2018 at 23:18 | comment | added | Kim | How does this rule out the possibility that $C_s$ might be irreducible? It is a union of fibers, yes. But perhaps the union is one fiber, and that fiber is connected? | |
| Jul 12, 2018 at 22:58 | comment | added | Dmitri Panov | You should not expect this. In the example that you consider the projection map from $C_s$ to the base has degree $0$. So its image will always be $0$-dimensional, i.e. $C_s$ will always be a union of fibres. | |
| Jul 12, 2018 at 22:52 | review | First posts | |||
| Jul 12, 2018 at 23:54 | |||||
| Jul 12, 2018 at 22:49 | history | asked | Kim | CC BY-SA 4.0 |