Timeline for Is $f(x)$ is more curvature than $g(x)$ then length of $f(x)$ seem longer than length of $g(x)$?
Current License: CC BY-SA 4.0
6 events
when toggle format | what | by | license | comment | |
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Jul 12, 2018 at 23:02 | vote | accept | Đào Thanh Oai | ||
Jul 12, 2018 at 21:57 | answer | added | Iosif Pinelis | timeline score: 7 | |
Jul 12, 2018 at 19:28 | review | Close votes | |||
Jul 14, 2018 at 17:35 | |||||
Jul 12, 2018 at 19:12 | comment | added | Alex M. | For simplicity, assume that $f'' \ge 0$ and $g'' \ge 0$ to get rid of the modulus, integrate on $[a,b]$ and see what you get. Next try the general case. This should have been asked on [Mathematics], though. | |
Jul 12, 2018 at 18:25 | history | edited | Đào Thanh Oai | CC BY-SA 4.0 |
added 54 characters in body
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Jul 12, 2018 at 18:16 | history | asked | Đào Thanh Oai | CC BY-SA 4.0 |