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Name of "this article" while the answer is bumped anyway
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LSpice
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Cauchy-SchwarzCauchy–Schwarz tells you that $$\sum_{i=1}^n |A_iA_{i+1}|^2\geq \frac{P^2}{n}$$$$\sum_{i=1}^n \lvert A_iA_{i+1}\rvert^2\geq \frac{P^2}{n}$$ where $P$ is the perimeter of the polygon. Then we need the inequality $$P^2\geq 4n\tan(\pi/n)A$$ which is the classical isoperimetric inequality for polygons with many proofs in the literature, analytic, geometric and algebraic. See thisFan, Taussky, and Todd - An algebraic proof of the isoperimetric inequality for polygons article and its references, for example.

Cauchy-Schwarz tells you that $$\sum_{i=1}^n |A_iA_{i+1}|^2\geq \frac{P^2}{n}$$ where $P$ is the perimeter of the polygon. Then we need the inequality $$P^2\geq 4n\tan(\pi/n)A$$ which is the classical isoperimetric inequality for polygons with many proofs in the literature, analytic, geometric and algebraic. See this article and its references, for example.

Cauchy–Schwarz tells you that $$\sum_{i=1}^n \lvert A_iA_{i+1}\rvert^2\geq \frac{P^2}{n}$$ where $P$ is the perimeter of the polygon. Then we need the inequality $$P^2\geq 4n\tan(\pi/n)A$$ which is the classical isoperimetric inequality for polygons with many proofs in the literature, analytic, geometric and algebraic. See Fan, Taussky, and Todd - An algebraic proof of the isoperimetric inequality for polygons article and its references, for example.

correct spelling
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coudy
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Cauchy Schwartz-Schwarz tells you that $$\sum_{i=1}^n |A_iA_{i+1}|^2\geq \frac{P^2}{n}$$ where $P$ is the perimeter of the polygon. Then we need the inequality $$P^2\geq 4n\tan(\pi/n)A$$ which is the classical isoperimetric inequality for polygons with many proofs in the literature, analytic, geometric and algebraic. See this article and its references, for example.

Cauchy Schwartz tells you that $$\sum_{i=1}^n |A_iA_{i+1}|^2\geq \frac{P^2}{n}$$ where $P$ is the perimeter of the polygon. Then we need the inequality $$P^2\geq 4n\tan(\pi/n)A$$ which is the classical isoperimetric inequality for polygons with many proofs in the literature, analytic, geometric and algebraic. See this article and its references, for example.

Cauchy-Schwarz tells you that $$\sum_{i=1}^n |A_iA_{i+1}|^2\geq \frac{P^2}{n}$$ where $P$ is the perimeter of the polygon. Then we need the inequality $$P^2\geq 4n\tan(\pi/n)A$$ which is the classical isoperimetric inequality for polygons with many proofs in the literature, analytic, geometric and algebraic. See this article and its references, for example.

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Gjergji Zaimi
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Cauchy Schwartz tells you that $$\sum_{i=1}^n |A_iA_{i+1}|^2\geq \frac{P^2}{n}$$ where $P$ is the perimeter of the polygon. Then we need the inequality $$P^2\geq 4n\tan(\pi/n)A$$ which is the classical isoperimetric inequality for polygons with many proofs in the literature, analytic, geometric and algebraic. See this article and its references, for example.