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Jul 11, 2018 at 11:08 review Close votes
Jul 11, 2018 at 21:04
Jul 7, 2018 at 19:28 comment added Gro-Tsen I'm not sure about your matrix equations, but let me confirm that the dimension of the Borel subgroup of type $C_n$ is $n^2+n$ (the full flag variety has dimension $n^2$), so $6$ when $n=2$.
Jul 7, 2018 at 18:53 comment added YCor To compute it, it's easier to first work in the Lie algebra where everything is linear, and then exponentiate. I don' remember if J has the right form to make it lower triangular; possibly the antidiagonal matrix $(1,1,-1,-1)$ is better.
Jul 7, 2018 at 18:01 history edited Jianrong Li CC BY-SA 4.0
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Jul 7, 2018 at 17:41 history asked Jianrong Li CC BY-SA 4.0