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Jul 7, 2018 at 21:50 history edited Bombyx mori CC BY-SA 4.0
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Jul 7, 2018 at 21:48 history made wiki Post Made Community Wiki by Bombyx mori
Jul 7, 2018 at 17:18 comment added Elle Najt Although, for a metric cycle graph, where the edge length scales down, then the volume ratio also goes to zero (like $n (1/n)^{n-1}$).
Jul 7, 2018 at 17:15 comment added Elle Najt Thanks! I think I understand your objection to the volume ratio now: since the determinant of the Laplacian of the circle is the Riemann zeta function regardless of scale, this ratio goes to zero as the circle grows. This is unlike a cycle graph, where the number of spanning trees (determinant / volume ratio) grows as the cycle grows.
Jul 7, 2018 at 16:42 history answered Bombyx mori CC BY-SA 4.0