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Jul 5, 2018 at 12:51 history edited YCor CC BY-SA 4.0
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Jul 5, 2018 at 12:04 answer added Gro-Tsen timeline score: 6
Jul 5, 2018 at 10:23 comment added YCor So it's enough to find a division ring and an injective, non-surjective endomorphism. Consider the free group over $(x_n)_{n\ge 0}$, and the endomorphism induced by $x_n\mapsto x_{n+1}$. Extend it to an endomorphism of the group ring (over some given field $k$). This is an Ore domain, so I guess this extends to an injective, non-surjective endomorphism of the right division ring of fractions, whose center is reduced to $k$. But I haven't checked details.
Jul 5, 2018 at 9:52 history asked user15749 CC BY-SA 4.0