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I have a very specific question. How does one check the following map ${\mathbb C}^n-\bigcup_{i\neq j} \{\text{z | z_i= $\pm$ z_j}\}\to {({\mathbb C}^*)}^{n-1}-\bigcup_{i\neq j}\{\text{w | w_i= w_j}\}$${\mathbb C}^n-\bigcup_{i\neq j} \{z \mid z_i= \pm z_j\}\to {({\mathbb C}^*)}^{n-1}-\bigcup_{i\neq j}\{w \mid w_i= w_j\}$ defined by $(z_1,z_2,\dotsc , z_n)\mapsto (z_n^2-z_1^2,\dotsc , z_n^2-z_{n-1}^2)$ is a locally trivial fibration? This is stated in the paper of E. Brieskorn ‘Sur les groupes de tresses’.

Actually, in the paper there are few other above type maps are defined and mentioned to be locally trivial fibration. Probably, there is some standard technique to check. Any hint, how to prove it?

I have a very specific question. How does one check the following map ${\mathbb C}^n-\bigcup_{i\neq j} \{\text{z | z_i= $\pm$ z_j}\}\to {({\mathbb C}^*)}^{n-1}-\bigcup_{i\neq j}\{\text{w | w_i= w_j}\}$ defined by $(z_1,z_2,\dotsc , z_n)\mapsto (z_n^2-z_1^2,\dotsc , z_n^2-z_{n-1}^2)$ is a locally trivial fibration? This is stated in the paper of E. Brieskorn ‘Sur les groupes de tresses’.

Actually, in the paper there are few other above type maps are defined and mentioned to be locally trivial fibration. Probably, there is some standard technique to check. Any hint, how to prove it?

I have a very specific question. How does one check the following map ${\mathbb C}^n-\bigcup_{i\neq j} \{z \mid z_i= \pm z_j\}\to {({\mathbb C}^*)}^{n-1}-\bigcup_{i\neq j}\{w \mid w_i= w_j\}$ defined by $(z_1,z_2,\dotsc , z_n)\mapsto (z_n^2-z_1^2,\dotsc , z_n^2-z_{n-1}^2)$ is a locally trivial fibration? This is stated in the paper of E. Brieskorn ‘Sur les groupes de tresses’.

Actually, in the paper there are few other above type maps are defined and mentioned to be locally trivial fibration. Probably, there is some standard technique to check. Any hint, how to prove it?

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RKS
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I have a very specific question. How does one check the following map ${\mathbb C}^n-\bigcup \{\text{\(z_i=\pm z_j\) for \(i\neq j\)}\}\to {({\mathbb C}^*)}^{n-1}-\bigcup\{\text{\(z_i= z_j\) for \(i\neq j\)}\}$${\mathbb C}^n-\bigcup_{i\neq j} \{\text{z | z_i= $\pm$ z_j}\}\to {({\mathbb C}^*)}^{n-1}-\bigcup_{i\neq j}\{\text{w | w_i= w_j}\}$ defined by $(z_1,z_2,\dotsc , z_n)\mapsto (z_n^2-z_1^2,\dotsc , z_n^2-z_{n-1}^2)$ is a locally trivial fibration? This is stated in the paper of E. Brieskorn ‘Sur les groupes de tresses’.

Actually, in the paper there are few other above type maps are defined and statedmentioned to be locally trivial fibration. Probably, there is some standard technique to check. Any hint, how to prove it?

I have a very specific question. How does one check the following map ${\mathbb C}^n-\bigcup \{\text{\(z_i=\pm z_j\) for \(i\neq j\)}\}\to {({\mathbb C}^*)}^{n-1}-\bigcup\{\text{\(z_i= z_j\) for \(i\neq j\)}\}$ defined by $(z_1,z_2,\dotsc , z_n)\mapsto (z_n^2-z_1^2,\dotsc , z_n^2-z_{n-1}^2)$ is a locally trivial fibration? This is stated in the paper of E. Brieskorn ‘Sur les groupes de tresses’.

Actually, in the paper there are few other above type maps are defined and stated to be locally trivial fibration. Probably, there is some standard technique to check. Any hint, how to prove it?

I have a very specific question. How does one check the following map ${\mathbb C}^n-\bigcup_{i\neq j} \{\text{z | z_i= $\pm$ z_j}\}\to {({\mathbb C}^*)}^{n-1}-\bigcup_{i\neq j}\{\text{w | w_i= w_j}\}$ defined by $(z_1,z_2,\dotsc , z_n)\mapsto (z_n^2-z_1^2,\dotsc , z_n^2-z_{n-1}^2)$ is a locally trivial fibration? This is stated in the paper of E. Brieskorn ‘Sur les groupes de tresses’.

Actually, in the paper there are few other above type maps are defined and mentioned to be locally trivial fibration. Probably, there is some standard technique to check. Any hint, how to prove it?

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A question on ‘Sur les groupes de tresses’ by Egbert Brieskorn

I have a very specific question. How does one check the following map ${\mathbb C}^n-\bigcup \{\text{\(z_i=\pm z_j\) for \(i\neq j\)}\}\to {({\mathbb C}^*)}^{n-1}-\bigcup\{\text{\(z_i= z_j\) for \(i\neq j\)}\}$ defined by $(z_1,z_2,\dotsc , z_n)\mapsto (z_n^2-z_1^2,\dotsc , z_n^2-z_{n-1}^2)$ is a locally trivial fibration? This is stated in the paper of E. Brieskorn ‘Sur les groupes de tresses without proof.

Actually, in the paper there are few other above type maps are defined and stated to be locally trivial fibration. Probably, there is some standard technique to check. Any hint, how to prove it?

A question on ‘Sur les groupes de tresses’ by Egbert Brieskorn

I have a very specific question. How does one check the following map ${\mathbb C}^n-\bigcup \{\text{\(z_i=\pm z_j\) for \(i\neq j\)}\}\to {({\mathbb C}^*)}^{n-1}-\bigcup\{\text{\(z_i= z_j\) for \(i\neq j\)}\}$ defined by $(z_1,z_2,\dotsc , z_n)\mapsto (z_n^2-z_1^2,\dotsc , z_n^2-z_{n-1}^2)$ is a locally trivial fibration? This is stated in the paper of E. Brieskorn ‘Sur les groupes de tresses without proof.

Actually, in the paper there are few other above type maps are defined and stated to be locally trivial fibration. Probably, there is some standard technique to check.

‘Sur les groupes de tresses’ by Egbert Brieskorn

I have a very specific question. How does one check the following map ${\mathbb C}^n-\bigcup \{\text{\(z_i=\pm z_j\) for \(i\neq j\)}\}\to {({\mathbb C}^*)}^{n-1}-\bigcup\{\text{\(z_i= z_j\) for \(i\neq j\)}\}$ defined by $(z_1,z_2,\dotsc , z_n)\mapsto (z_n^2-z_1^2,\dotsc , z_n^2-z_{n-1}^2)$ is a locally trivial fibration? This is stated in the paper of E. Brieskorn ‘Sur les groupes de tresses’.

Actually, in the paper there are few other above type maps are defined and stated to be locally trivial fibration. Probably, there is some standard technique to check. Any hint, how to prove it?

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