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Jun 28, 2018 at 15:18 comment added Johannes Hahn And of course the answer depends on the underlying field. If you use a finite field, the orthogonal groups are finite and therefore satisfy a lot of nontrivial relations, for example relations like $x^{|G|} =1$
Jun 28, 2018 at 14:00 comment added HJRW You might like to look at this: en.wikipedia.org/wiki/Tits_alternative . The group $O(2)$ is virtually abelian. For larger $n$, $O(n)$ contains a free subgroup, and in particular satisfies no law.
Jun 28, 2018 at 13:23 history asked Mikhail Tikhomirov CC BY-SA 4.0