Timeline for In what sense bibundles are called as generalized morphisms
Current License: CC BY-SA 4.0
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| Jun 15, 2020 at 7:27 | history | edited | CommunityBot |
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| Jul 6, 2018 at 20:54 | vote | accept | Praphulla Koushik | ||
| Jul 4, 2018 at 5:25 | answer | added | David Roberts♦ | timeline score: 2 | |
| Jun 30, 2018 at 7:48 | history | edited | Praphulla Koushik | CC BY-SA 4.0 |
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| Jun 29, 2018 at 11:35 | comment | added | Praphulla Koushik | @NicolaCiccoli Please let me know if you can say little more than that... | |
| Jun 29, 2018 at 11:30 | history | edited | Praphulla Koushik | CC BY-SA 4.0 |
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| Jun 28, 2018 at 9:41 | comment | added | Praphulla Koushik | @NicolaCiccoli Sir, It looks like I understand but I do not :D :D All I can say is that you mean suppose there is a bibundle $P:\mathcal{G}\rightarrow \mathcal{H}$ that is a principal $\mathcal{G}$ bundle then $\mathcal{G}$ and $\mathcal{H}$ are Morita equivalent. Am I correct? If that is the case, that would give sufficient justification for not considering bibundle that is principal on both sides.. Now, can you tell me what pull back you are talking here when you say pull back of $\mathcal{G}$ and $\mathcal{H}$? | |
| Jun 28, 2018 at 8:38 | comment | added | Nicola Ciccoli | You use pullback to give a groupoid morphism between a pullback of $\mathcal G$ and $\mathcal H$. The role of the two actions are not symmetric because tour generalized morphism has a direction. If you ask both principality conditions you get an invertible generalized morphism, thus a Morita equivalence. | |
| Jun 27, 2018 at 13:06 | history | edited | Praphulla Koushik | CC BY-SA 4.0 |
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| Jun 27, 2018 at 11:53 | history | edited | Praphulla Koushik | CC BY-SA 4.0 |
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| Jun 27, 2018 at 7:59 | history | edited | Praphulla Koushik | CC BY-SA 4.0 |
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| Jun 27, 2018 at 4:46 | history | asked | Praphulla Koushik | CC BY-SA 4.0 |