Timeline for Finding a particular matrix factor
Current License: CC BY-SA 4.0
5 events
when toggle format | what | by | license | comment | |
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Jun 26, 2018 at 19:20 | vote | accept | Ludwig | ||
Jun 26, 2018 at 15:47 | comment | added | Alex Gavrilov | For $|x|\le 1$ the function $a(x)$ is analytic by the assumption (1), and $a(x^{-1})$ is analytic because numerator and denominator are analytic and the latter is not zero. | |
Jun 26, 2018 at 15:43 | comment | added | Alex Gavrilov | Without (2) the argument doesn't work because the denominator could turn zero. | |
Jun 26, 2018 at 14:56 | comment | added | Ludwig | Thanks for the answer! Could you please elaborate a little more on your sentence "assuming (1) and (2), the function $a(x)$ would be analytic both for $|x|\le 1$ and for $|x|\ge 1$"? In particular, how is requirement (2) applied here? | |
Jun 26, 2018 at 12:32 | history | answered | Alex Gavrilov | CC BY-SA 4.0 |