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Jun 27, 2018 at 14:53 comment added Andreas Thom I edited the last sentence to clarify the meaning.
Jun 27, 2018 at 13:10 comment added Andreas Thom Yes, exactly. No proper power of $\chi^2$ is golden.
Jun 27, 2018 at 13:10 history edited Andreas Thom CC BY-SA 4.0
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Jun 27, 2018 at 9:41 comment added Matthew Daws Doesn't Andreas say that $\chi^{2n}$ is golden if and only if $n=0$ or $1$. So $\chi^4$ is your counter-example... I think?
Jun 27, 2018 at 8:44 comment added MSMalekan But $\chi^2=2+\delta_2+\delta_{-2}$ is golden so this is not the counterexample!
Jun 27, 2018 at 7:25 history edited Andreas Thom CC BY-SA 4.0
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Jun 27, 2018 at 6:37 vote accept MSMalekan
Jun 27, 2018 at 8:41
Jun 26, 2018 at 21:36 history edited Andreas Thom CC BY-SA 4.0
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Jun 26, 2018 at 12:14 history answered Andreas Thom CC BY-SA 4.0