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Jun 27, 2018 at 7:29 comment added Naren Manjunath @QiaochuYuan Thanks. I didn't know the finiteness condition. I am trying to interpret 'central extension' as the group of symmetries on a two-dimensional lattice in the presence of a magnetic field (for a fixed field, the translation operators determine a projective representation of $\mathbb Z^2$). So different extensions would correspond to different magnetic fields, and I would not expect there to be a universal central extension for this problem.
Jun 26, 2018 at 23:19 comment added Qiaochu Yuan People use "Schur multiplier" to refer to both $H_2(G, \mathbb{Z})$ and $H^2(G, \mathbb{C}^{\times})$ for $G$ a finite group because they are (noncanonically) isomorphic in that case, which they aren't in general. Also, the universal central extension is an extension of $G$ by $H_2(G, \mathbb{Z})$ and it only exists in general if $G$ is perfect, which $\mathbb{Z}^2$ isn't.
Jun 26, 2018 at 11:10 vote accept Naren Manjunath
Jun 26, 2018 at 8:54 answer added Francesco Polizzi timeline score: 7
Jun 26, 2018 at 8:03 review Close votes
Jun 26, 2018 at 9:30
Jun 26, 2018 at 7:28 review First posts
Jun 26, 2018 at 7:35
Jun 26, 2018 at 7:28 history asked Naren Manjunath CC BY-SA 4.0