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Jun 23, 2018 at 19:46 comment added Ali Taghavi Thanks again for sharing such a very interesting paper. I will read it carefuly. But it is strange : It seems that there is a possible contradictory situation. The example in the previous example shows that $Z$ is not an ideal!.
Jun 23, 2018 at 8:24 history edited j.c. CC BY-SA 4.0
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Jun 23, 2018 at 8:17 comment added Ali Taghavi Thanks a lot for your answer and the reference. In dimension $2$(n=1) $E(M,\omega)=\chi^{\infty}(M)$. But I think that $Z$ is not an ideal in $E$. For example $y\partial_x -x\partial_y \in Z,\;\;x^2\partial_x \in E$ but their Lie braket is $2xy\partial_x+x^2\partial_y $ is not in $Z$.
Jun 23, 2018 at 8:00 history answered Nicola Ciccoli CC BY-SA 4.0