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Jun 20, 2018 at 12:35 comment added Gro-Tsen @AaronMeyerowitz I'm not sure I understand your comment, but the vector spaces with $4$ or $8$ elements are unproblematic and fall under the purview of the split (direct sum) case I mentioned in my previous paragraph (and which is also what you mention in your own answer); I don't think there's much to say about them. What I was trying to give a sample of, with $Z_4$ and $Q$, were various problematic cases where I think one needs to think about what one wants to admit or reject. (Should $Z_4$ be considered a "vector multispace"? I don't know. But it makes sense to think about it.)
Jun 20, 2018 at 4:15 comment added Aaron Meyerowitz Instead of $\mathbb{Z}_4$ and $Q$ why not actual vector spaces with $4$ or $8$ elements?
Jun 19, 2018 at 12:35 history answered Gro-Tsen CC BY-SA 4.0