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Jun 19, 2018 at 23:52 comment added Trevor Wilson @Asaf Do you mean that ZF + ($\ast$) implies $\aleph_1^V$ is strong limit in $L$? I don't even see why it would imply that $\aleph_1^L < \aleph_1$. In light of the result of Martin and Solovay I mentioned, we would need to do something with $\kappa$-Suslin sets for some $\kappa > \aleph_1$, but I don't know what.
Jun 19, 2018 at 21:59 comment added Asaf Karagila Well. If $\omega_1$ is regular, the lower bound would be at least an inaccessible, almost automatically. My guess you can get probably get something like some large cardinal using some absoluteness.
Jun 19, 2018 at 15:32 history edited Trevor Wilson CC BY-SA 4.0
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Jun 19, 2018 at 15:31 comment added Trevor Wilson @Asaf I would be interested in the answer either way (as written, or with DC). The equiconsistency that I mentioned holds with or without DC added. The model of ($\ast$) + "$\Theta = \aleph_2$" that I obtain from a model of ZFC + "there is a generic Vopěnka cardinal" satisfies DC, but the reverse direction does not require any kind of choice principle.
Jun 19, 2018 at 7:14 comment added Asaf Karagila I am guessing that you also want DC there, or at least DC(R), right?
Jun 17, 2018 at 0:32 history asked Trevor Wilson CC BY-SA 4.0