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Jun 14, 2018 at 14:22 comment added Jochen Wengenroth Of course, the support of a distribution is closed. If it is contained in $(0,\infty)$ there is a strictly positive $a$ such that it is contained in $[a,\infty)$.
Jun 14, 2018 at 10:37 vote accept Lucia
Jun 14, 2018 at 10:28 answer added Jochen Wengenroth timeline score: 4
Jun 14, 2018 at 10:09 vote accept Lucia
Jun 14, 2018 at 10:37
Jun 14, 2018 at 10:09 vote accept Lucia
Jun 14, 2018 at 10:09
Jun 14, 2018 at 9:51 answer added jarauh timeline score: 2
Jun 14, 2018 at 9:27 comment added abx How do you define the support of a distribution? For me this is a closed subset of $\Bbb{R}$.
Jun 14, 2018 at 9:03 comment added YCor Is convolution really well-defined in this setting? (double checking, it seems so)
Jun 14, 2018 at 8:22 history asked Lucia CC BY-SA 4.0