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Jun 9, 2022 at 15:42 history edited Martin Sleziak CC BY-SA 4.0
http -> https (the question was bumped anyway)
Jun 13, 2018 at 15:51 comment added Mike Shulman This is a good point. In tripos-theoretic language, these are the "weakly complete" sets. The absence of PUC seems only to matter for "predicative" sets whose construction doesn't involve powersets, such as $\mathbb{N},\mathbb{Z},\mathbb{Q}$, and the ordinary Cauchy reals. And I wouldn't be surprised if PUC also held automatically, at least in some contexts, for sets like $\mathbb{N},\mathbb{Z},\mathbb{Q}$ that can be defined without any quotients, i.e. such that their setoid equality is Leibniz equality.
Jun 13, 2018 at 4:35 history answered James CC BY-SA 4.0