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Jun 10, 2018 at 21:19 comment added meh @ Ritwik Sorry, bpf = base point free as Roy says. The first reference I found on the web for the lemma is math.lsa.umich.edu/~mmustata/hw9.pdf which gives an application of the sort you are looking for.
Jun 10, 2018 at 19:33 comment added roy smith base point free, I believe.
Jun 10, 2018 at 18:21 comment added Ritwik @aginensky: What is bpf?
Jun 10, 2018 at 16:11 comment added meh easier to see :)
Jun 10, 2018 at 16:00 comment added meh I would add to what Mohan, a man of inestimable reputation, said. For curves one can sometimes use the bpf pencil trick. That is if $L_1$ is bpf, then the vanishing of of $H^1(L_2 \otimes L_1^{-1} ) $ is a sufficient criteria. Of course S doesn't have to be a curve for this criteria to be true, but for curves that vanishing is usually easy to see.
Jun 10, 2018 at 15:44 history answered Mohan CC BY-SA 4.0