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Jun 12, 2018 at 15:55 comment added Michael Albanese Such an example would provide an answer to this question.
Jun 12, 2018 at 12:44 comment added Michael Albanese @YonatanHarpaz: You're right. I realised this last night, but I couldn't think of an example where $w_3 = 0$ but $W_3 \neq 0$. Do you know of such an example?
Jun 12, 2018 at 9:47 comment added Yonatan Harpaz There is a small subtlety here to take into account: the $w_3$ appearing in Browder's theorem lives in $H^3(X,\mathbb{Z}/2)$, and is equal to $Sq^1w_2$. The vanishing of $w_3$ is hence not equivalence to $w_2$ having an integral lift, but to $w_2$ having a lift to $H^2(X,\mathbb{Z}/4)$. The obstruction to $w_2$ having an integral lift is a certain class in $H^3(X,\mathbb{Z})$ which lifts $w_3$.
Jun 10, 2018 at 16:32 history edited j.c. CC BY-SA 4.0
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Jun 10, 2018 at 14:48 history answered Michael Albanese CC BY-SA 4.0