Timeline for How to prove $\sum_{k=1}^{\frac{p-1}{2}}\frac{(-1)^k}{k}\sum_{i=\lfloor k/2\rfloor +1}^k\frac{1}{2i-1}\equiv 0\pmod{p}$?
Current License: CC BY-SA 4.0
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| when toggle format | what | by | license | comment | |
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| Jun 9, 2018 at 5:57 | history | edited | Chitsai Liu | CC BY-SA 4.0 |
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| Jun 9, 2018 at 5:36 | history | edited | Chitsai Liu | CC BY-SA 4.0 |
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| Jun 9, 2018 at 5:27 | history | answered | Chitsai Liu | CC BY-SA 4.0 |