Timeline for Does separability of the strong operator topology imply separability of the underlying space?
Current License: CC BY-SA 4.0
4 events
when toggle format | what | by | license | comment | |
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Jun 9, 2018 at 17:08 | comment | added | Tomasz Kania | @FanZheng absolutely. | |
Jun 9, 2018 at 4:17 | comment | added | Fan Zheng | So it looks like $|B(X)|=\frak c$ is superfluous. | |
Jun 8, 2018 at 9:07 | vote | accept | ABB | ||
Jun 8, 2018 at 8:40 | history | answered | Tomasz Kania | CC BY-SA 4.0 |