Timeline for The existence of $v\in A\otimes_{\mathbb{K}}A$ such that $(a\otimes_{\mathbb{K}}1)v=(1\otimes_{\mathbb{K}}a)v$
Current License: CC BY-SA 4.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jun 4, 2018 at 11:57 | comment | added | darij grinberg | Suggestion: Nakayama's determinant trick :) Not a big deal, but I've gotten used to seeing at least one determinantal trick per proof, and those aren't all the same. | |
| Jun 4, 2018 at 11:50 | comment | added | Neil Strickland | @darijgrinberg Matsumura calls that result Nakayama's Lemma, but many other people use that name just for the statement $\mathfrak{m}M=M\Rightarrow M=0$. I am no historian and do not really have an opinion. | |
| Jun 4, 2018 at 11:31 | history | edited | darij grinberg | CC BY-SA 4.0 |
added 9 characters in body
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| Jun 4, 2018 at 11:31 | comment | added | darij grinberg | "the standard determinant trick" also known as Nakayama's lemma :) | |
| Jun 4, 2018 at 11:28 | history | answered | Neil Strickland | CC BY-SA 4.0 |