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Jun 16, 2018 at 13:56 vote accept zeraoulia rafik
Jun 2, 2018 at 9:12 history edited Carlo Beenakker CC BY-SA 4.0
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Jun 2, 2018 at 2:50 comment added zeraoulia rafik I'm confused how you calculated the coeffecients of series using error function ?
Jun 1, 2018 at 18:08 comment added Carlo Beenakker @zeraouliarafik -- when I say $I_{50}=0.816377$ I am referring to the sum $I_{N}=\sum_{p=0}^N c_p$, which is the series expansion of $I(t)$ for $t=1$ to order 50; what you have evaluated with Wolfram alpha is $I(t)$ for $t=50$, which is a different thing.
Jun 1, 2018 at 17:02 comment added zeraoulia rafik The value of I(50) from wolfram alpha is : 0.972107 , wolframalpha.com/input/…
Jun 1, 2018 at 13:36 history edited Carlo Beenakker CC BY-SA 4.0
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Jun 1, 2018 at 13:05 comment added zeraoulia rafik But is it possible to get it for n th term and it's seems that is a formel power series ?
Jun 1, 2018 at 9:46 history edited Carlo Beenakker CC BY-SA 4.0
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Jun 1, 2018 at 9:41 history edited Carlo Beenakker CC BY-SA 4.0
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Jun 1, 2018 at 9:03 history edited Carlo Beenakker CC BY-SA 4.0
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Jun 1, 2018 at 8:36 history edited Carlo Beenakker CC BY-SA 4.0
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Jun 1, 2018 at 8:23 history answered Carlo Beenakker CC BY-SA 4.0