Timeline for Closed form of :$\int_{-1}^1 x^{2k} (\operatorname{erf}(x))^k \,dx $ for $ k$ is even integer and :$\int _{0}^{t}\exp(-x^2 \operatorname{erf}(x))dx$
Current License: CC BY-SA 4.0
12 events
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Jun 16, 2018 at 13:56 | vote | accept | zeraoulia rafik | ||
Jun 2, 2018 at 9:12 | history | edited | Carlo Beenakker | CC BY-SA 4.0 |
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Jun 2, 2018 at 2:50 | comment | added | zeraoulia rafik | I'm confused how you calculated the coeffecients of series using error function ? | |
Jun 1, 2018 at 18:08 | comment | added | Carlo Beenakker | @zeraouliarafik -- when I say $I_{50}=0.816377$ I am referring to the sum $I_{N}=\sum_{p=0}^N c_p$, which is the series expansion of $I(t)$ for $t=1$ to order 50; what you have evaluated with Wolfram alpha is $I(t)$ for $t=50$, which is a different thing. | |
Jun 1, 2018 at 17:02 | comment | added | zeraoulia rafik | The value of I(50) from wolfram alpha is : 0.972107 , wolframalpha.com/input/… | |
Jun 1, 2018 at 13:36 | history | edited | Carlo Beenakker | CC BY-SA 4.0 |
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Jun 1, 2018 at 13:05 | comment | added | zeraoulia rafik | But is it possible to get it for n th term and it's seems that is a formel power series ? | |
Jun 1, 2018 at 9:46 | history | edited | Carlo Beenakker | CC BY-SA 4.0 |
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Jun 1, 2018 at 9:41 | history | edited | Carlo Beenakker | CC BY-SA 4.0 |
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Jun 1, 2018 at 9:03 | history | edited | Carlo Beenakker | CC BY-SA 4.0 |
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Jun 1, 2018 at 8:36 | history | edited | Carlo Beenakker | CC BY-SA 4.0 |
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Jun 1, 2018 at 8:23 | history | answered | Carlo Beenakker | CC BY-SA 4.0 |