Timeline for $G$-Invariant Differential Operators
Current License: CC BY-SA 4.0
2 events
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May 30, 2018 at 19:59 | comment | added | S. carmeli | It is not true. For example multiplication by a non-constant function is $G_a$-invariant for every $a$ because it factors through the quotient by $m_a$ and the action on the quotient is trivial of course (it is just $\mathbb{C}$). | |
May 30, 2018 at 19:39 | history | asked | freeRmodule | CC BY-SA 4.0 |