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May 30, 2018 at 20:57 history edited Solar Galaxy CC BY-SA 4.0
deleted 45 characters in body
May 30, 2018 at 20:51 vote accept Solar Galaxy
May 30, 2018 at 17:33 history edited Luc Guyot CC BY-SA 4.0
Fixes a typo
May 30, 2018 at 16:50 history edited Luc Guyot CC BY-SA 4.0
Adds some links and fixes some typos
May 29, 2018 at 21:37 answer added Pietro Majer timeline score: 15
May 29, 2018 at 21:14 history edited Solar Galaxy CC BY-SA 4.0
edited body
May 29, 2018 at 21:08 history edited Solar Galaxy CC BY-SA 4.0
added 1 character in body
May 29, 2018 at 20:51 comment added Pietro Majer OK, so $A=\cup_n A_n$, right?
May 29, 2018 at 20:18 comment added Solar Galaxy @PietroMajer $A_n$ is set of angles of all triangles till $n$-th step (you're true: $6^n$ triangles in $n$-th step +$6^{n-1}$ in $n-1$-th step+...+1=$\sum_{i=0}^{n} 6^i$ tiangles) ,leads $A_n$ has $3×\sum_{i=0}^{n} 6^i$ angles. Our goal is to find a dense $A$ on $(0,\pi)$
May 29, 2018 at 19:55 review Close votes
May 30, 2018 at 7:54
May 29, 2018 at 19:37 comment added Pietro Majer Is perhaps $A_n$ the set of $6^n$ triangles of the $n$-th barycentric subdivision of $T$?
May 29, 2018 at 19:36 comment added Pietro Majer The sentence starting with "In $(n+1)$-th step" sounds obscure, even grammatically. Is $A_n$ a set of angles or a set of triangles? What is the meaning of "$\lim_n A_n$"? What is the meaning of "$A$ is dense on $(0,\pi)$"? What is "our goal"? Thank you
May 29, 2018 at 19:09 history asked Solar Galaxy CC BY-SA 4.0