Timeline for Is there a triangle which makes dense set of angles by drawing medians?
Current License: CC BY-SA 4.0
13 events
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May 30, 2018 at 20:57 | history | edited | Solar Galaxy | CC BY-SA 4.0 |
deleted 45 characters in body
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May 30, 2018 at 20:51 | vote | accept | Solar Galaxy | ||
May 30, 2018 at 17:33 | history | edited | Luc Guyot | CC BY-SA 4.0 |
Fixes a typo
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May 30, 2018 at 16:50 | history | edited | Luc Guyot | CC BY-SA 4.0 |
Adds some links and fixes some typos
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May 29, 2018 at 21:37 | answer | added | Pietro Majer | timeline score: 15 | |
May 29, 2018 at 21:14 | history | edited | Solar Galaxy | CC BY-SA 4.0 |
edited body
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May 29, 2018 at 21:08 | history | edited | Solar Galaxy | CC BY-SA 4.0 |
added 1 character in body
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May 29, 2018 at 20:51 | comment | added | Pietro Majer | OK, so $A=\cup_n A_n$, right? | |
May 29, 2018 at 20:18 | comment | added | Solar Galaxy | @PietroMajer $A_n$ is set of angles of all triangles till $n$-th step (you're true: $6^n$ triangles in $n$-th step +$6^{n-1}$ in $n-1$-th step+...+1=$\sum_{i=0}^{n} 6^i$ tiangles) ,leads $A_n$ has $3×\sum_{i=0}^{n} 6^i$ angles. Our goal is to find a dense $A$ on $(0,\pi)$ | |
May 29, 2018 at 19:55 | review | Close votes | |||
May 30, 2018 at 7:54 | |||||
May 29, 2018 at 19:37 | comment | added | Pietro Majer | Is perhaps $A_n$ the set of $6^n$ triangles of the $n$-th barycentric subdivision of $T$? | |
May 29, 2018 at 19:36 | comment | added | Pietro Majer | The sentence starting with "In $(n+1)$-th step" sounds obscure, even grammatically. Is $A_n$ a set of angles or a set of triangles? What is the meaning of "$\lim_n A_n$"? What is the meaning of "$A$ is dense on $(0,\pi)$"? What is "our goal"? Thank you | |
May 29, 2018 at 19:09 | history | asked | Solar Galaxy | CC BY-SA 4.0 |