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Jun 1, 2018 at 17:17 vote accept user173856
Jun 1, 2018 at 17:16 comment added user173856 Gerhard Paseman: Thanks for your answer!
May 29, 2018 at 16:31 comment added Gerhard Paseman One can refine the lower bound estimate by picking a larger set while guaranteeing each two members intersect in a set of size 3 or larger. One gets a lower bound which is $(1 - c/\sqrt{n})^m$ times $2^{nm - m}$ for some not big constant $c$. Gerhard "Close Enough For Envelope Back" Paseman, 2018.05.29.
May 29, 2018 at 16:19 history answered Gerhard Paseman CC BY-SA 4.0