Skip to main content
13 events
when toggle format what by license comment
May 29, 2018 at 6:42 vote accept Sergei Akbarov
May 28, 2018 at 7:41 comment added Sergei Akbarov Pietro, it's OK, I did not suspect this. I read about the difference here: mathforum.org/library/drmath/view/52249.html So now I know about it. :)
May 28, 2018 at 7:20 comment added Pietro Majer My apologies, I didn't mean to be nitpicking :)
May 28, 2018 at 6:45 history edited Sergei Akbarov CC BY-SA 4.0
edited body
May 28, 2018 at 6:25 comment added Sergei Akbarov @PietroMajer, actually I don't feel the difference, my English is not that good.
May 28, 2018 at 3:46 comment added Pietro Majer (But why "hypothesis"? You are stating it as a conjecture, aren't you?)
May 28, 2018 at 2:18 answer added Robert Furber timeline score: 9
May 27, 2018 at 22:10 answer added Michael Greinecker timeline score: 13
May 27, 2018 at 21:18 history edited Sergei Akbarov
edited tags
May 27, 2018 at 20:20 answer added billabong timeline score: 2
May 27, 2018 at 19:53 comment added Michael Greinecker It is sufficient, but I have no appropriate reference at hand. Every bounded linear functional on $L_\infty(\mu)$ can be represented as integration with respect to a finite finitely additive signed measure absolutely continuous with respect to $\mu$. Each such finitely additive signed measure has a Jordan decomposition and the rest is a standard characterization of countable additivity for bounded finitely additive set functions by the measure of sequences of sets decreasing to the empty set decreasing to zero.
May 27, 2018 at 19:01 history edited Sergei Akbarov CC BY-SA 4.0
deleted 2 characters in body
May 27, 2018 at 18:14 history asked Sergei Akbarov CC BY-SA 4.0