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May 26, 2018 at 18:02 vote accept asv
May 26, 2018 at 16:52 answer added Alex M. timeline score: 1
May 26, 2018 at 16:44 comment added asv @fedja: Thanks. It seems to be the final answer.
May 26, 2018 at 16:43 comment added asv @NateEldredge: Most probably you are right.
May 26, 2018 at 16:35 comment added fedja Assuming Nate's interpretation, any bounded from below $V$ will do and, moreover, any $V(x)\ge -o(x^2)$ is fine too (just use Jensen and the fact that $X(\tau)$ is Gaussian for all $\tau$).
May 26, 2018 at 16:04 comment added Nate Eldredge So to rephrase this in probabilistic notation, it seems that you're looking for $\mathbb{E}[\exp(-\int_0^L V(X(\tau))\,d\tau)]$ where $X$ is a Brownian bridge starting at $a$ and ending at $b$.
May 26, 2018 at 13:25 history edited asv CC BY-SA 4.0
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May 26, 2018 at 12:56 history asked asv CC BY-SA 4.0