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May 29, 2018 at 1:24 comment added Ben Wieland Yes, $2n+k+1$. General position gives $2n+k+2$ and the Whitney trick peels off another dimension. The key is to rewrite $\pi_iEmb(M,\mathbb R^n)$ as a map $M\times S^i\to \mathbb R^n\times S^i$. This is much better than $M\times S^i\to\mathbb R^n$. It is redundant (and you have to make sure that such redundancy is preserved as you manipulate it), but the self-intersections of such maps are the obstruction to parameterized embedding. Extend to a map $M\times D^{i+1}\to \mathbb R^n\times D^{i+1}$. Apply general position to this new map.
May 22, 2018 at 13:41 history edited Saal Hardali CC BY-SA 4.0
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May 22, 2018 at 12:08 history edited Saal Hardali CC BY-SA 4.0
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May 22, 2018 at 11:49 history edited Saal Hardali CC BY-SA 4.0
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May 22, 2018 at 11:42 history asked Saal Hardali CC BY-SA 4.0