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Timeline for Solving a "reversed" Stein equation

Current License: CC BY-SA 4.0

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Dec 1, 2023 at 20:28 comment added Ali Taghavi @SpencerKraisler My apology for my late repley. To be honest the answer I provided in the post was based on immediate computation. It was not based on a reference on Stein equation. at the time of answering I was not aware of the special terminology, i.e stein equation, for such equation. So I do not know any resource on the topic. I will come back you if I find some resources
Nov 28, 2023 at 19:17 comment added Spencer Kraisler @AliTaghavi Could you recommend any resources on inverse solutions to the Stein equation?
May 21, 2018 at 3:21 vote accept Ludwig
May 20, 2018 at 23:57 comment added Mahdi - Free Palestine Yes, that is right. Thanks for the response.
May 20, 2018 at 21:39 history edited Ali Taghavi CC BY-SA 4.0
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May 20, 2018 at 20:53 comment added Ali Taghavi @Mahdi Thanks for your comment. Yes you are completely right. the spectrum is invariant under cyclic permutation. But our extra assumption $PQ=QP$ implies that the permutation I used is actualy a cyclic permutation. Right?
May 20, 2018 at 20:27 comment added Mahdi - Free Palestine I can't follow this "the spectrum of the solution $X={(P-Q)}^{1/2}T P^{-1/2}$ is equal to the spectrum of $T{(P-Q)}^{1/2}P^{-1/2}$ because $AB$ and $BA$ have the same spectrum". The later statement implies just that the spectrum of the product of some matrices is invariant under cyclic permutation, not every permutation. am I missing something?
May 20, 2018 at 20:05 history edited Ali Taghavi CC BY-SA 4.0
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May 20, 2018 at 7:59 history answered Ali Taghavi CC BY-SA 4.0