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May 18, 2018 at 6:29 comment added Qiaochu Yuan I think one has to say a bit more to fully answer the OP's question. Here's a start: suppose you have two PNNOs in a suitable category. Since PNNOs are defined by a universal property there is a unique isomorphism between them compatible with the inclusion of $1$ and the successor function. I think the OP's question is something like: what does it mean for this isomorphism itself to be computable? Or is this even a useful / interesting / meaningful question?
May 18, 2018 at 4:00 history edited François G. Dorais CC BY-SA 4.0
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May 18, 2018 at 0:27 comment added Andreas Blass The $G$ described in the last sentence of your answer seems to be the relation defined by $f(\vec n,m)=0$, which need not be the graph of a function. You need to cut down $G$ to contain only one point per fiber; in other words, the projection from $G$ to $\mathbf N^k$ needs to be an isomorphism, not just a regular epi.
May 17, 2018 at 21:25 comment added François G. Dorais Yes, @DavidRoberts, fixed now.
May 17, 2018 at 21:25 history edited François G. Dorais CC BY-SA 4.0
added 2 characters in body
May 17, 2018 at 20:52 comment added David Roberts Is there a k missing in your commutative square?
May 17, 2018 at 20:07 history answered François G. Dorais CC BY-SA 4.0