Timeline for Point spectrum of a positive invertible operator
Current License: CC BY-SA 4.0
5 events
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May 15, 2018 at 8:28 | comment | added | Robert Israel | I was considering $\widehat{f}(x) = \sum_{k=-\infty}^\infty f(k) e^{ikx}$ which extends from $[0,2\pi)$ to an entire function on $\mathbb C$. Of course the two points of view are equivalent. | |
May 14, 2018 at 20:49 | comment | added | Jochen Glueck | @RobertIsrael: Good point! I can't resist, though, to point out the following two things: (i) The dual group of $\mathbb{Z}$ is the complex unit circle $\mathbb{T}$, so I guess you'd rather consider the set $\{z \in \mathbb{T}: \hat f(z) = t\}$; (ii) The Fourier transform $\hat f$ is a rational function which might have a pole at $0$. (Or did I missunderstand you and you would like to consider the function $\hat f(x) := \sum_{k=-\infty}^\infty f(k) e^{ikx}$ rather than $\hat f(z) := \sum_{k=-\infty}^\infty f(k)z^k$)? | |
May 14, 2018 at 20:14 | comment | added | Robert Israel | ... and this is essentially the only example on $\mathbb Z$. That is, if $f$ has finite support in $\mathbb Z$, $\widehat{f}$ extends to an entire function, so if $\{x \in \mathbb R:\; \widehat{f}(x) = t\}$ has positive measure it must be all of $\mathbb R$, and $T_f$ is a constant multiple of the identity. | |
May 14, 2018 at 18:16 | history | edited | Jochen Glueck | CC BY-SA 4.0 |
added 120 characters in body
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May 14, 2018 at 17:23 | history | answered | Jochen Glueck | CC BY-SA 4.0 |