Timeline for Can this sum be majorized?
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
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| May 14, 2018 at 1:58 | comment | added | fedja | Take $m=2$, $r_1=1$, $r_2=0.5$. | |
| May 14, 2018 at 0:11 | comment | added | Greg Martin | Certainly not: take $r_i=z_i$ for every $i\ne2$ and take $r_2 > z_2$; then $S_1-S_2 = -\binom m2 (r_2-z_2) < 0$. | |
| May 13, 2018 at 23:58 | comment | added | anonymous_man | (removed old comment). kodlu; thanks for the answer. I've somehow ill-phrased the problem; and overly-generalized it. I need $f(x)=x$; $z_i=r_i^2$ (simply, the first sum with $r_i$'s and the second with $r_i^2$'s). | |
| May 13, 2018 at 23:57 | history | edited | anonymous_man | CC BY-SA 4.0 |
added 235 characters in body
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| May 13, 2018 at 23:49 | history | edited | anonymous_man | CC BY-SA 4.0 |
added 19 characters in body
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| May 13, 2018 at 23:36 | comment | added | kodlu | A simple numerical experiment throws up a lot of false instances of your inequality for $f(x)=x(2-x)$ for $m=2,3,\ldots,10.$ | |
| May 13, 2018 at 23:14 | review | First posts | |||
| May 13, 2018 at 23:42 | |||||
| May 13, 2018 at 23:12 | history | asked | anonymous_man | CC BY-SA 4.0 |