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Feb 3, 2022 at 19:09 history edited LSpice CC BY-SA 4.0
Proofreading; link to specific answer and specific comment; F_1 -> \Fun for uniformity
Feb 3, 2022 at 18:32 answer added Sam Hopkins timeline score: 2
Feb 3, 2022 at 18:23 history edited YCor CC BY-SA 4.0
formatting
S Feb 3, 2022 at 18:13 history suggested Jukka Kohonen CC BY-SA 4.0
Fix some typos.
Feb 3, 2022 at 16:26 review Suggested edits
S Feb 3, 2022 at 18:13
May 11, 2018 at 22:01 comment added Sam Hopkins There are probably things to be said about $[n]_q!$ as counting the number of points of the full flag variety over $\mathbb{F}_q$, but this is very closely related to, and generally more trivial than, than the case of Grasmannians
May 11, 2018 at 21:25 comment added Alexander Chervov @RichardStanley I mean same q-Catalan as in Gjergji Zaimi question: $\frac{1}{[n+1]_q}\left[{2n\atop n}\right]_q$ . But any other suggestions are welcome. Is there any identity on any q-Catalan which can be lifted to geometric identity ?
May 11, 2018 at 20:45 comment added Richard Stanley You say that the $q$-Catalan number itself is NOT the number of points of any smooth projective variety over $\mathbf{F}_q$. Which $q$-Catalan number do you mean? The $q$-Catalan number $c_n(0;q)$ of Problem A43(f) of my book Catalan Numbers has symmetric unimodal coefficients so could conceivably count points on a smooth projective variety over $\mathbf{F}_q$.
May 11, 2018 at 20:29 history asked Alexander Chervov CC BY-SA 4.0